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3.5x^2-28x-504=0
a = 3.5; b = -28; c = -504;
Δ = b2-4ac
Δ = -282-4·3.5·(-504)
Δ = 7840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7840}=\sqrt{784*10}=\sqrt{784}*\sqrt{10}=28\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28\sqrt{10}}{2*3.5}=\frac{28-28\sqrt{10}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28\sqrt{10}}{2*3.5}=\frac{28+28\sqrt{10}}{7} $
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